Tribute to a very special woman...

The following was written by one of my daughters. It expresses what each of
us feels every day after six years...
A little boy walks by alone on the sidewa...
1 month ago
Answer: There must have been a point where the winning percentage was exactly 80%, but there need not have been a point where it was exactly 70%.
ReplyDeleteConsider the first time that the team reached or exceeded 80%. Say that they have played N games, and won k of them. Thus k/N >= 4/5.
Since this was the first time they reached 80%, the team must have won the Nth game. So, they had only k1 wins after N1 games, and (k1)/(N1) < 4/5.
Now, (k1)/(N1) < 4/5 is equivalent to 4N > 5k1, and k/N >= 4/5 is equivalent to 4N <= 5k.
Since 4N is an integer, and there are no integers between 5k1 and 5k, we conclude that 4N = 5k, or k = 4/5 N. Thus, the winning percentage was exactly 80% after N games.
For the other part of the question, note that if the team loses the first game and wins the next nine games, then the winning percentage will never be exactly 70%.