Area Man Who Talks a Lot About Teaching Teaches His First Full Day in >10
Years
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I have taught demo and observational classes regularly since I left
full-time teaching but yesterday was the first time I taught every class
for the day. L...
3 years ago
The answer is c = f((a+b)/2).
ReplyDeleteSince f is continuous and increasing, it has an inverse function g. By turning the graph sideways, we see that the area A(c) is given by the following equation.
A(c) = int (f(a) to c) [g(x) - a] dx + int (c to f(b)) [b - g(x)] dx.
Using the fundamental theorem of calculus,
A'(c) = 2g(c) - a - b,
so the minimum area occurs when A'(c) = 0, or when g(c) = (a+b)/2, which is equivalent to c = f((a+b)/2).